Stumped on LG - PrepTest 34, Game 4 Forum

[UCSD1984]

Been staring at rules and combinations of rules for this game for about an hour. A full break-down would be nice, since I only got 3 of the 6 correct, and one of them was a guess between 2 non-eliminated choices. Thank you in advance, I appreciate the time.

Edit: I'm going to do the game again and start completely over with the rules. By the time I get home tonight I'll recheck this thread to see what exactly I missed out on as far as the rules and their combinations/interactions (assuming someone replies).

Thank you again.

[510Chicken]

J K L N O P
r/s

1. J(s) -> K(r)
2. J(r) -> O(s) [+ N(s)]
3. L(s) -> N(r) + P(r)
4. N(r) -> O(r)
5. P(r) -> O(s) + K(s) [+ N(s)]

--- The Brackets are additions due to the following inferences ---
2+3. J(r) -> O(s) + N(s)
-If "O" is at (s), then "N" cannot be at (r) and must be at (s) as well
4+5. P(r) -> K(s) + O(s) + N(s)
-Same as above.
3+4+5. L(r)
-L cannot be at (s). Otherwise, rules will come in conflict.
----3+4. L(s) -> N(r) + P(r) + O(r)
----3+4+5. L(s) -> N(r) + P(r) + O(r) + O(s) + K(s)

Those are the rules I had before I even began solving the questions. I just kept summing the rules up as I wrote them down in the beginning.

[510Chicken]

19.
A) J cannot be at (s) with K (Rule 1)
B) This is correct
C) If J is at (r), then both O and N must be at (s) (Rule 2*). We know J is at (r) because it is omitted from the list for (s).
D) (Rule 5) If P is at (r) (being omitted), then K must be at (s).
E) (Rule 2) If J is at (r), O must be at (s).

20. P(r)
---> K(s) + O(s) + N(s)
K(s) -> J(r)
-This is the contrapositive of Rule 1
"A"

22. N <-/-> O
--> O(r) + N(s) (Rule 4)
---> O(r) + N(s) + J(s) (Rule 2*)
"A"

23.
Rule 5*
P(r) -> O(s) + K(s) [+ N(s)]
"E"

24. K(s)
--> J(r) (Rule 1)
---> J(r) + O(s) + N(s) (Rule 2*)
"B"

Dunno if that helps. It looks kinda convoluted. Also, 21 is too hard for me to type up. Sorry.