$ v. $$ v. $$$ Forum

[NoLieAbility]

What does each term denote? Is it a measured by 1-9 = $, 10-99 = $$, and 100+ = $$$? Is there a set format that is used?

This feels like something that I should have been able to find for myself, but I'll be damned if I could find it.

[malleus discentium]

$ vs $$ vs $$$ are relative rather than absolute markers. Some people assign quartiles to them ($ is 25% tuition, $$ half etc.) but that's not standard and inferring any absolute rather than relative value from $ vs $$ vs $$$ isn't going to be useful.

[Clyde Frog]

$$$$

[ManoftheHour]

$$$$

[Nucky]

If you have to ask, you can't afford it.

[John Everyman]

Asked this question a little while ago and was nearly unanimously told quartile percentages. Not sure why anyone would be against establishing a standard here.

[transferror]

If you have to ask, you can't afford it.

[TheSpanishMain]

$$$$ > $.

[Clyde Frog]

$$+$$=$$$$

[ManoftheHour]

$$$$-$$=$$

[Sinatra]

$x=?, if x=4?

[ScottRiqui]

S + I = $

[Nova]

$x=?, if x=4?

$$$$

[ManoftheHour]

$x=?, if x=4?

x=?/$, 4=?/$

[Clyde Frog]

$$$$

[ManoftheHour]

$$$$

[TheSpanishMain]

££££

[Attax]

$$^2=$$$$

[ScottRiqui]

$$^2=$$$$

Shame on you - should be $$$.

[John Everyman]

√$$$$ = $$

[Attax]

$$^2=$$$$

Shame on you - should be $$$.

Why's that? $$^2 = $$*$$=$$$$ and $$$$^(1/2)=$$

But what'd d/d$ f($$)?

[ScottRiqui]

$$^2=$$$$

Shame on you - should be $$$.

Why's that? $$^2 = $$*$$=$$$$ and $$$$^(1/2)=$$

But what'd d/d$ f($$)?

Exponentiation before multiplication, remember? Only the second '$' gets squared, then you multiply the result by the first '$' to give you $$$.

[Attax]

$$^2=$$$$

Shame on you - should be $$$.

Why's that? $$^2 = $$*$$=$$$$ and $$$$^(1/2)=$$

But what'd d/d$ f($$)?

Exponentiation before multiplication, remember? Only the second '$' gets squared, then you multiply the result by the first '$' to give you $$$.

Oh, I meant $$ as like a representation of 2 total. But in that case, since only the second $ gets squared and it is a singular unit it would be $*$^2 where $^2=$ thus $$^2=$$

[ScottRiqui]

Oh, I meant $$ as like a representation of 2 total. But in that case, since only the second $ gets squared and it is a singular unit it would be $*$^2 where $^2=$ thus $$^2=$$

Just do use parentheses, bro:

($$)^2 = $$$$

[Attax]

Oh, I meant $$ as like a representation of 2 total. But in that case, since only the second $ gets squared and it is a singular unit it would be $*$^2 where $^2=$ thus $$^2=$$

Just do use parentheses, bro:

($$)^2 = $$$$

What do you think I am? A STEM person?!?!?!

So then d/d$ of f($$) where f($$)=($$)^2 would = 2($$)

The world is pure again!