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LSAT averages

Posted: Tue Nov 02, 2010 5:19 pm
by marsilni
Does your score get rounded up if you have a 0.5?

I just got 168 in October...if my average with December's test is 171.5, do I get a 172?

Re: LSAT averages

Posted: Tue Nov 02, 2010 5:20 pm
by im_blue
Schools almost always take your higher score.

Re: LSAT averages

Posted: Tue Nov 02, 2010 8:31 pm
by hiddenfist
im_blue wrote:Schools almost always take your higher score.
Not true, a lot of schools use this formula:

((x/100) + (y/180 x 100)) x 100 = z

Where x is your first LSAT, y is your second LSAT, and z is the score they use to calculate your index.

You don't even want to see the formula if you take it a third time...

Re: LSAT averages

Posted: Tue Nov 02, 2010 8:32 pm
by Ragged
hiddenfist wrote:
im_blue wrote:Schools almost always take your higher score.
Not true, a lot of schools use this formula:

((x/100) + (y/180 x 100)) x 100 = z

Where x is your first LSAT, y is your second LSAT, and z is the score they use to calculate your index.

You don't even want to see the formula if you take it a third time...
I'd like to see it.

Re: LSAT averages

Posted: Tue Nov 02, 2010 8:34 pm
by hiddenfist
Ragged wrote:
hiddenfist wrote:
im_blue wrote:Schools almost always take your higher score.
Not true, a lot of schools use this formula:

((x/100) + (y/180 x 100)) x 100 = z

Where x is your first LSAT, y is your second LSAT, and z is the score they use to calculate your index.

You don't even want to see the formula if you take it a third time...
I'd like to see it.
I'll PM it to you, not sure if law schools would like me spilling their secrets on the web.

Re: LSAT averages

Posted: Wed Nov 03, 2010 8:54 am
by marsilni
hiddenfist wrote:
im_blue wrote:Schools almost always take your higher score.
Not true, a lot of schools use this formula:

((x/100) + (y/180 x 100)) x 100 = z

Where x is your first LSAT, y is your second LSAT, and z is the score they use to calculate your index.

You don't even want to see the formula if you take it a third time...
How does this equation work...with hypothetical #'s:

[(168/100) + (174/180 x 100)] x 100 = 9834.666

What does 9834.666 mean?

The straight up average between those scores is 171.

Re: LSAT averages

Posted: Wed Nov 03, 2010 8:56 am
by ech41989
Do most schools do this? I was under the impression that most just took your higher score, but now I'm nervous...I got a 165 in June (fluke) and 170 in October...167.5 will not get me where I'm trying to go :/

Re: LSAT averages

Posted: Wed Nov 03, 2010 8:59 am
by InLikeFlint
hiddenfist wrote:
im_blue wrote:Schools almost always take your higher score.
Not true, a lot of schools use this formula:

((x/100) + (y/180 x 100)) x 100 = z

Where x is your first LSAT, y is your second LSAT, and z is the score they use to calculate your index.

You don't even want to see the formula if you take it a third time...
Terrible flame is terrible.

Re: LSAT averages

Posted: Wed Nov 03, 2010 10:04 am
by 2014
hiddenfist wrote:
im_blue wrote:Schools almost always take your higher score.
Not true, a lot of schools use this formula:

((x/100) + (y/180 x 100)) x 100 = z

Where x is your first LSAT, y is your second LSAT, and z is the score they use to calculate your index.

You don't even want to see the formula if you take it a third time...
Pretty sure you pulled that out of your ass.

Re: LSAT averages

Posted: Wed Nov 03, 2010 10:10 pm
by marsilni
Schools can report only the high score when being considered in the annual rankings, so I would think it would be to their benefit to accept an applicant with a high score, regardless of whether or not it was on their first or second attempt. If you go from 168 to 177 and have a good GPA, why wouldn't they want to consider the only 177?

Back to my original question though....is an averaged score like 171.5 considered a 172?

Re: LSAT averages

Posted: Thu Nov 04, 2010 4:24 pm
by Ragged
marsilni wrote:
Back to my original question though....is an averaged score like 171.5 considered a 172?
I think so. My average is 170.66. LSAC shows it as 171.