## PT 21 Section 1 Question 2

Prepare for the LSAT or discuss it with others in this forum.
Trig

Posts: 220
Joined: Tue Jul 02, 2013 3:36 pm

### PT 21 Section 1 Question 2

The credited answer is B, but B must be true (I think) while the question asks for what could be true.

Any help would be greatly appreciated. Thanks!

rinkrat19

Posts: 13923
Joined: Sat Sep 25, 2010 5:35 am

### Re: PT 21 Section 1 Question 2

Southbridge wrote:The credited answer is B, but B must be true (I think) while the question asks for what could be true.

Any help would be greatly appreciated. Thanks!

I'm not looking at a PT, but if something must be true, it also could be true. It falls somewhere on the possible scale.

Something that must be true can't be false, but it could be true.

CardozoLaw09

Posts: 2183
Joined: Sat Aug 28, 2010 1:58 pm

### Re: PT 21 Section 1 Question 2

Southbridge wrote:The credited answer is B, but B must be true (I think) while the question asks for what could be true.

Any help would be greatly appreciated. Thanks!

Yeah for this one it's the somewhat rare occurrence where something that could be true is also something that must be true. S or V can't go with L to make a double otherwise one of them (S or V) would constitute a single which would be a violation of one of the rules. Also, S and V can't be together with L because L can't be part of a triple. So B must be true.

Trig

Posts: 220
Joined: Tue Jul 02, 2013 3:36 pm

### Re: PT 21 Section 1 Question 2

With R forced to be a single, and KP needing to be an exclusive double, doesn't E need to be true also, i.e. there will be two exactly two doubles because LST can't work and neither S nor T can be on their own?

And if there must be exactly two doubles why is B credited over E?

Thanks!

CardozoLaw09

Posts: 2183
Joined: Sat Aug 28, 2010 1:58 pm

### Re: PT 21 Section 1 Question 2

Southbridge wrote:With R forced to be a single, and KP needing to be an exclusive double, doesn't E need to be true also, i.e. there will be two exactly two doubles because LST can't work and neither S nor T can be on their own?

And if there must be exactly two doubles why is B credited over E?

Thanks!

STV could make a triple, R could be the single, KP together for the double, and L alone for a single. Neither of S/V/T can make a double because then one of them would have to be alone which is not allowed OR one of them would have to be with L, but then there would be three rooms with doubles. Also, B is actually a could be true, because there's no reason why S/V/T cannot go with L to make a double.