## Prep test 29 Sec. 3 Game 4

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b33eazy

Posts: 146
Joined: Sun Jul 04, 2010 6:43 pm

### Prep test 29 Sec. 3 Game 4

I don't understand how K can be second if o must be first.. It clearly states that o is before K and G yet O is after K.. That makes no sense..

KaplanLSATInstructor

Posts: 53
Joined: Fri Sep 12, 2008 5:53 pm

### Re: Prep test 29 Sec. 3 Game 4

OP -- it appears you're talking about the last question... the only time it's mentioned that O is before G.

I'm wondering if you mistyped something in your message, because there seems to be some inconsistency. Here's a quick rundown of the question, in any event:

According to this question, it replaces the original rule of the game that O comes after G. NOW, the new rule is that O comes before G, but AFTER K. So, in order, you have K...O...G.

Based on the original rules of the game, K is the first female, but NOT the first person. So, someone else must be first.

Combining the rest of the rules, I and L are in a class together, which must come after K (since I is female and K has to be the first female) and also must come before G (based on the fourth rule). Also, P (along with two others) must come after G. So, what you have is somebody before K, which has to be before IL and before O, both of which have to be before G, which has to be before P (with two others). Since IL and O could be in either order, there are two possible sequences:

[someone]...K...IL...O...G...[P _ _] or [someone]... K ... O... IL...G ... [P _ _]

Since these sequences have six items in order, this is your strict ordering from 1-6. In other words, Someone is 1st, K is 2nd, IL and O are 3rd and 4th, G is 5th and P is 6th.

Who's left? H (a female), n (male) and s (male). Since H is female, she can't go 1st. (That would violate the third rule about Kate being the first female.) So, either n or s is first, meaning H has to be one of the two people in a class with P at the end -- in 6th. That's (E).

Hope this helps.

- Chris

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