## Pt 39 (Dec 2002) LG 3 (Pohls)

Prepare for the LSAT or discuss it with others in this forum.
beezneez

Posts: 22
Joined: Mon Apr 02, 2012 11:53 pm

### Pt 39 (Dec 2002) LG 3 (Pohls)

I feel so dumb today. I know I am missing something key - this is not a hard game! - but why can't the empty year be either 1994, 1995 or 1996, leaving you with the following 2nd template:

90 - Z/r
91 - S/l
92 - E/E
93 - U/r
94 - W-T-E/and corresponding left/right/empty as per original rules
95 - W-T-E/ " "
96 - W-T-E/ " "

For me "Hurdle the Uncertainties" has become "Hurdle the Stupidity," or maybe I need a break lol!

timmydoeslsat

Posts: 148
Joined: Wed Aug 03, 2011 2:07 pm

### Re: Pt 39 (Dec 2002) LG 3 (Pohls)

So we know that we have this for certain.

_ L _ R _ _ _
_ _ _ U _ _ _
0 1 2 3 4 5 6

Since we know we cannot have LL or RR, 1992 will be blank.

_ L X R _ _ _
_ _ X U _ _ _
0 1 2 3 4 5 6

We know that S must come before the U, and we know that S is left handed. S could not be in slot 0 as this would cause two L's to touch. Thus S must be in 1. As that is the only way to go prior to U.

_ L X R _ _ _
_ S X U _ _ _
0 1 2 3 4 5 6

We also have the sequence of Z before T and W. We have LL left to place and 1 R.

The first slot must either be blank or be a R. I will show this.

SLOT 1 AS BLANK:

X L X R _ _ _
X S X U _ _ _
0 1 2 3 4 5 6

This forces Z in 4, T/W to trade off in 5 and 6. We would have L be in 4 and 6 and R be in 5.

SLOT 1 AS R:

R L X R _ _ _
Z S X U _ _ _
0 1 2 3 4 5 6

This forces Z to be in 0. We only had 3 variables left, Z and T,W. Now we would have T and W trade off in slots 4 and 6 and they are L's. Slot 5 is X'd out.