I understand this game is not too difficult, but rather rare.
I have looked up Manhattan LSAT.
Yet, I cannot fully understand the problems as a whole, probably because I don't understand the wording as some of you may know....
Question:"In an odd-position round, teams in positions 3 and 5 play against teams positioned immediately above them." What does it mean by "above them"? Is it like position 1 and 2 will be above position 3 since the position 1 is the highest position?
I cannot make further step
If anybody have time, could you please help me out?
Thank you very much.
3 posts • Page 1 of 1
- Posts: 46
- Joined: Sun Nov 29, 2009 4:19 am
Yes, team 1 is positioned immediately above team 2, team 2 is positioned immediately above team 3, etc. So according to the rule you've cited, in an odd position round, teams 2 and 3 would play each other, teams 4 and 5 would play each other, and team 1 would not be playing in that round.
Who is online
Users browsing this forum: Yahoo [Bot] and 2 guests