LGB Chapter 7 Game 1 October 1997- #22 pg.306

ebm3q
Posts: 13
Joined: Sat Oct 02, 2010 10:45 pm

LGB Chapter 7 Game 1 October 1997- #22 pg.306

Postby ebm3q » Tue Feb 01, 2011 11:23 pm

I don't understand why S has to speak 5th twice. If a speaker speaks 5 ------> then they will speak first. but not vice versa. Why does this conditional statement reverse when normally this is not the case? Usually the LGB explanations are quite clear, but their explanation is a bit dense on this one. I would appreciate any help. Thank you very much!

JG7773
Posts: 333
Joined: Mon Mar 22, 2010 2:02 am

Re: LGB Chapter 7 Game 1 October 1997- #22 pg.306

Postby JG7773 » Tue Feb 01, 2011 11:51 pm

ebm3q wrote:I don't understand why S has to speak 5th twice. If a speaker speaks 5 ------> then they will speak first. but not vice versa. Why does this conditional statement reverse when normally this is not the case? Usually the LGB explanations are quite clear, but their explanation is a bit dense on this one. I would appreciate any help. Thank you very much!


Hopefully this will help. . .

1 - R ___ ____ _____ __S___
2 - R ___ ____ _____ ___S__
3- S ___ ____ _____ ___R__

Since we know that any speaker that speaks 5th must also speak first we know that R and S and the only one who can speak 5th. Since R can not speak twice at any given event, R would speak 5th at meeting three, thus forcing S to speak 5th at both 1 and 2.

ebm3q
Posts: 13
Joined: Sat Oct 02, 2010 10:45 pm

Re: LGB Chapter 7 Game 1 October 1997- #22 pg.306

Postby ebm3q » Sat Feb 05, 2011 1:35 pm

Ohhhhhh!!! I understand. Thank you so much. It's like one of those blatant things you miss when you are trying to look at the details. I didn't understand because I didn't apply the "can only speak once rule" to this problem. Again, Thanks!!




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