Page 1 of 1

PT40 Sec. 2 #17 (Games)

Posted: Fri Oct 29, 2010 6:31 pm
by 2011Law
For the love of god I do not understand this one. I'm doing fine on the more recent games, but this question is taunting me. Please help.

Re: PT40 Sec. 2 #17 (Games)

Posted: Fri Oct 29, 2010 6:55 pm
by 2011Law
Is everyone too busy hitting the refresh button waiting for scores?

Re: PT40 Sec. 2 #17 (Games)

Posted: Fri Oct 29, 2010 6:56 pm
by Hedwig
Ask again later.

Re: PT40 Sec. 2 #17 (Games)

Posted: Sat Oct 30, 2010 8:42 am
by Manhattan LSAT Noah
There's a discussion of the game here: http://www.manhattanlsat.com/forums/pre ... g-f35.html

Re: PT40 Sec. 2 #17 (Games)

Posted: Tue Nov 02, 2010 9:30 pm
by 2011Law
Manhattan LSAT Noah wrote:There's a discussion of the game here: http://www.manhattanlsat.com/forums/pre ... g-f35.html
Thanks for pointing me in the right direction... fml I'm dumb. On the upside, Andrew Shrivell has given me inspiration that even dumb people can get anywhere in life.

Re: PT40 Sec. 2 #17 (Games)

Posted: Tue Nov 02, 2010 9:31 pm
by 2011Law
Also, hey eit. lol

Re: PT40 Sec. 2 #17 (Games)

Posted: Tue Nov 02, 2010 11:28 pm
by jlhero
all hard lg's have a very important inference.

i just did this game today, the key inference is that Vancouver can pair with all 4 others. and only by doing this we can know what is the maximum # of pairs.

i think the only hard question in this game is 16, 17 shouldnt be hard

Re: PT40 Sec. 2 #17 (Games)

Posted: Tue Nov 02, 2010 11:43 pm
by 2011Law
jlhero wrote:i just did this game today, the key inference is that Vancouver can pair with all 4 others. and only by doing this we can know what is the maximum # of pairs.
When Vancouver is paired with the four other cities, then you only have four pairs of cities connected, not five as is the maximum (which I got from doing #12). I think the only question that inference helps with (but is key for) is 17.

Re: PT40 Sec. 2 #17 (Games)

Posted: Wed Nov 03, 2010 1:03 am
by jlhero
no...... you need to also consider that TP is the only pair left possible. so the max is 5

Re: PT40 Sec. 2 #17 (Games)

Posted: Wed Nov 03, 2010 1:09 am
by 2011Law
jlhero wrote:no...... you need to also consider that TP is the only pair left possible. so the max is 5
The max is five, like I said, which you get by doing #12. But when V is connected with T P H and M, T and P cannot be connected, as per the last rule, hence there are only four connections with 17.

/thread

Re: PT40 Sec. 2 #17 (Games)

Posted: Wed Nov 03, 2010 1:16 am
by jlhero
ya, i must have remembered something wrong.

but my point is, by noticing that Vancouver is able to pair with all others, i pretty much answered all questions easily.