stratocophic wrote:Not sure, but I think you can use DiffEQ to solve for the second solution, because the quadratic formula's obviously not going to work

You can't use differential equations - if you simplify first, you'd just get 2x - 2 = 0. Differentiate and you'd get 2 = 0. This answer is not significant either way (doesn't tell us whether we have a solution or not)

Take this problem/example:

x - 4 = 0

If you differentiate, you get 1 = 0. But we know that there's a solution (x = 4).

@ ptblazer NP. I was gonna write out the multiple ways to solve the above, but I thought it'd just be too much to read.